Optimal. Leaf size=184 \[ \frac{d (c+d x) \cos (a+b x)}{4 b^2}-\frac{d (c+d x) \cos (3 a+3 b x)}{72 b^2}-\frac{d (c+d x) \cos (5 a+5 b x)}{200 b^2}-\frac{d^2 \sin (a+b x)}{4 b^3}+\frac{d^2 \sin (3 a+3 b x)}{216 b^3}+\frac{d^2 \sin (5 a+5 b x)}{1000 b^3}+\frac{(c+d x)^2 \sin (a+b x)}{8 b}-\frac{(c+d x)^2 \sin (3 a+3 b x)}{48 b}-\frac{(c+d x)^2 \sin (5 a+5 b x)}{80 b} \]
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Rubi [A] time = 0.189954, antiderivative size = 184, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 3, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125, Rules used = {4406, 3296, 2637} \[ \frac{d (c+d x) \cos (a+b x)}{4 b^2}-\frac{d (c+d x) \cos (3 a+3 b x)}{72 b^2}-\frac{d (c+d x) \cos (5 a+5 b x)}{200 b^2}-\frac{d^2 \sin (a+b x)}{4 b^3}+\frac{d^2 \sin (3 a+3 b x)}{216 b^3}+\frac{d^2 \sin (5 a+5 b x)}{1000 b^3}+\frac{(c+d x)^2 \sin (a+b x)}{8 b}-\frac{(c+d x)^2 \sin (3 a+3 b x)}{48 b}-\frac{(c+d x)^2 \sin (5 a+5 b x)}{80 b} \]
Antiderivative was successfully verified.
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Rule 4406
Rule 3296
Rule 2637
Rubi steps
\begin{align*} \int (c+d x)^2 \cos ^3(a+b x) \sin ^2(a+b x) \, dx &=\int \left (\frac{1}{8} (c+d x)^2 \cos (a+b x)-\frac{1}{16} (c+d x)^2 \cos (3 a+3 b x)-\frac{1}{16} (c+d x)^2 \cos (5 a+5 b x)\right ) \, dx\\ &=-\left (\frac{1}{16} \int (c+d x)^2 \cos (3 a+3 b x) \, dx\right )-\frac{1}{16} \int (c+d x)^2 \cos (5 a+5 b x) \, dx+\frac{1}{8} \int (c+d x)^2 \cos (a+b x) \, dx\\ &=\frac{(c+d x)^2 \sin (a+b x)}{8 b}-\frac{(c+d x)^2 \sin (3 a+3 b x)}{48 b}-\frac{(c+d x)^2 \sin (5 a+5 b x)}{80 b}+\frac{d \int (c+d x) \sin (5 a+5 b x) \, dx}{40 b}+\frac{d \int (c+d x) \sin (3 a+3 b x) \, dx}{24 b}-\frac{d \int (c+d x) \sin (a+b x) \, dx}{4 b}\\ &=\frac{d (c+d x) \cos (a+b x)}{4 b^2}-\frac{d (c+d x) \cos (3 a+3 b x)}{72 b^2}-\frac{d (c+d x) \cos (5 a+5 b x)}{200 b^2}+\frac{(c+d x)^2 \sin (a+b x)}{8 b}-\frac{(c+d x)^2 \sin (3 a+3 b x)}{48 b}-\frac{(c+d x)^2 \sin (5 a+5 b x)}{80 b}+\frac{d^2 \int \cos (5 a+5 b x) \, dx}{200 b^2}+\frac{d^2 \int \cos (3 a+3 b x) \, dx}{72 b^2}-\frac{d^2 \int \cos (a+b x) \, dx}{4 b^2}\\ &=\frac{d (c+d x) \cos (a+b x)}{4 b^2}-\frac{d (c+d x) \cos (3 a+3 b x)}{72 b^2}-\frac{d (c+d x) \cos (5 a+5 b x)}{200 b^2}-\frac{d^2 \sin (a+b x)}{4 b^3}+\frac{(c+d x)^2 \sin (a+b x)}{8 b}+\frac{d^2 \sin (3 a+3 b x)}{216 b^3}-\frac{(c+d x)^2 \sin (3 a+3 b x)}{48 b}+\frac{d^2 \sin (5 a+5 b x)}{1000 b^3}-\frac{(c+d x)^2 \sin (5 a+5 b x)}{80 b}\\ \end{align*}
Mathematica [A] time = 1.01095, size = 252, normalized size = 1.37 \[ -\frac{-6750 b^2 c^2 \sin (a+b x)+1125 b^2 c^2 \sin (3 (a+b x))+675 b^2 c^2 \sin (5 (a+b x))-13500 b^2 c d x \sin (a+b x)+2250 b^2 c d x \sin (3 (a+b x))+1350 b^2 c d x \sin (5 (a+b x))-6750 b^2 d^2 x^2 \sin (a+b x)+1125 b^2 d^2 x^2 \sin (3 (a+b x))+675 b^2 d^2 x^2 \sin (5 (a+b x))-13500 b d (c+d x) \cos (a+b x)+750 b d (c+d x) \cos (3 (a+b x))+270 b c d \cos (5 (a+b x))+13500 d^2 \sin (a+b x)-250 d^2 \sin (3 (a+b x))-54 d^2 \sin (5 (a+b x))+270 b d^2 x \cos (5 (a+b x))}{54000 b^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.02, size = 484, normalized size = 2.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.17677, size = 506, normalized size = 2.75 \begin{align*} -\frac{3600 \,{\left (3 \, \sin \left (b x + a\right )^{5} - 5 \, \sin \left (b x + a\right )^{3}\right )} c^{2} - \frac{7200 \,{\left (3 \, \sin \left (b x + a\right )^{5} - 5 \, \sin \left (b x + a\right )^{3}\right )} a c d}{b} + \frac{3600 \,{\left (3 \, \sin \left (b x + a\right )^{5} - 5 \, \sin \left (b x + a\right )^{3}\right )} a^{2} d^{2}}{b^{2}} + \frac{30 \,{\left (45 \,{\left (b x + a\right )} \sin \left (5 \, b x + 5 \, a\right ) + 75 \,{\left (b x + a\right )} \sin \left (3 \, b x + 3 \, a\right ) - 450 \,{\left (b x + a\right )} \sin \left (b x + a\right ) + 9 \, \cos \left (5 \, b x + 5 \, a\right ) + 25 \, \cos \left (3 \, b x + 3 \, a\right ) - 450 \, \cos \left (b x + a\right )\right )} c d}{b} - \frac{30 \,{\left (45 \,{\left (b x + a\right )} \sin \left (5 \, b x + 5 \, a\right ) + 75 \,{\left (b x + a\right )} \sin \left (3 \, b x + 3 \, a\right ) - 450 \,{\left (b x + a\right )} \sin \left (b x + a\right ) + 9 \, \cos \left (5 \, b x + 5 \, a\right ) + 25 \, \cos \left (3 \, b x + 3 \, a\right ) - 450 \, \cos \left (b x + a\right )\right )} a d^{2}}{b^{2}} + \frac{{\left (270 \,{\left (b x + a\right )} \cos \left (5 \, b x + 5 \, a\right ) + 750 \,{\left (b x + a\right )} \cos \left (3 \, b x + 3 \, a\right ) - 13500 \,{\left (b x + a\right )} \cos \left (b x + a\right ) + 27 \,{\left (25 \,{\left (b x + a\right )}^{2} - 2\right )} \sin \left (5 \, b x + 5 \, a\right ) + 125 \,{\left (9 \,{\left (b x + a\right )}^{2} - 2\right )} \sin \left (3 \, b x + 3 \, a\right ) - 6750 \,{\left ({\left (b x + a\right )}^{2} - 2\right )} \sin \left (b x + a\right )\right )} d^{2}}{b^{2}}}{54000 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.499786, size = 470, normalized size = 2.55 \begin{align*} -\frac{270 \,{\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right )^{5} - 150 \,{\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right )^{3} - 900 \,{\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right ) -{\left (450 \, b^{2} d^{2} x^{2} + 900 \, b^{2} c d x - 27 \,{\left (25 \, b^{2} d^{2} x^{2} + 50 \, b^{2} c d x + 25 \, b^{2} c^{2} - 2 \, d^{2}\right )} \cos \left (b x + a\right )^{4} + 450 \, b^{2} c^{2} +{\left (225 \, b^{2} d^{2} x^{2} + 450 \, b^{2} c d x + 225 \, b^{2} c^{2} + 22 \, d^{2}\right )} \cos \left (b x + a\right )^{2} - 856 \, d^{2}\right )} \sin \left (b x + a\right )}{3375 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 11.5424, size = 382, normalized size = 2.08 \begin{align*} \begin{cases} \frac{2 c^{2} \sin ^{5}{\left (a + b x \right )}}{15 b} + \frac{c^{2} \sin ^{3}{\left (a + b x \right )} \cos ^{2}{\left (a + b x \right )}}{3 b} + \frac{4 c d x \sin ^{5}{\left (a + b x \right )}}{15 b} + \frac{2 c d x \sin ^{3}{\left (a + b x \right )} \cos ^{2}{\left (a + b x \right )}}{3 b} + \frac{2 d^{2} x^{2} \sin ^{5}{\left (a + b x \right )}}{15 b} + \frac{d^{2} x^{2} \sin ^{3}{\left (a + b x \right )} \cos ^{2}{\left (a + b x \right )}}{3 b} + \frac{4 c d \sin ^{4}{\left (a + b x \right )} \cos{\left (a + b x \right )}}{15 b^{2}} + \frac{26 c d \sin ^{2}{\left (a + b x \right )} \cos ^{3}{\left (a + b x \right )}}{45 b^{2}} + \frac{52 c d \cos ^{5}{\left (a + b x \right )}}{225 b^{2}} + \frac{4 d^{2} x \sin ^{4}{\left (a + b x \right )} \cos{\left (a + b x \right )}}{15 b^{2}} + \frac{26 d^{2} x \sin ^{2}{\left (a + b x \right )} \cos ^{3}{\left (a + b x \right )}}{45 b^{2}} + \frac{52 d^{2} x \cos ^{5}{\left (a + b x \right )}}{225 b^{2}} - \frac{856 d^{2} \sin ^{5}{\left (a + b x \right )}}{3375 b^{3}} - \frac{338 d^{2} \sin ^{3}{\left (a + b x \right )} \cos ^{2}{\left (a + b x \right )}}{675 b^{3}} - \frac{52 d^{2} \sin{\left (a + b x \right )} \cos ^{4}{\left (a + b x \right )}}{225 b^{3}} & \text{for}\: b \neq 0 \\\left (c^{2} x + c d x^{2} + \frac{d^{2} x^{3}}{3}\right ) \sin ^{2}{\left (a \right )} \cos ^{3}{\left (a \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.11354, size = 282, normalized size = 1.53 \begin{align*} -\frac{{\left (b d^{2} x + b c d\right )} \cos \left (5 \, b x + 5 \, a\right )}{200 \, b^{3}} - \frac{{\left (b d^{2} x + b c d\right )} \cos \left (3 \, b x + 3 \, a\right )}{72 \, b^{3}} + \frac{{\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right )}{4 \, b^{3}} - \frac{{\left (25 \, b^{2} d^{2} x^{2} + 50 \, b^{2} c d x + 25 \, b^{2} c^{2} - 2 \, d^{2}\right )} \sin \left (5 \, b x + 5 \, a\right )}{2000 \, b^{3}} - \frac{{\left (9 \, b^{2} d^{2} x^{2} + 18 \, b^{2} c d x + 9 \, b^{2} c^{2} - 2 \, d^{2}\right )} \sin \left (3 \, b x + 3 \, a\right )}{432 \, b^{3}} + \frac{{\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2} - 2 \, d^{2}\right )} \sin \left (b x + a\right )}{8 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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